-6v^2-13v-6=0

Solution for -6v^2-13v-6=0 equation:

-6v^2-13v-6=0

a = -6; b = -13; c = -6;
Δ = b2-4ac
Δ = -132-4·(-6)·(-6)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*-6}=\frac{8}{-12}
=-2/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*-6}=\frac{18}{-12}
=-1+1/2
$